Users often ask how much electrical cost they will experience operating a pump or aerator motor.  Simple enough to determine using information found on the motor or manufacture’s literature and a bill from their electric company.

The basic formula to calculate electric cost per hour is;

Cost per Hour =  Kw x $ per KwHr

Where;

  • Kw                  Motor kilowatt rating.  Find on motor label or in manufacturer literature.
  • $ per KwHr     How much the electric company charges.  Find on a recent bill or call them.

Example:  A 2 Hp motor has a kilowatt rating of 2.19 Kw.  Electric cost is $.09 per KwHr.  So,

  • Cost per Hour =  2.19 Kw  x  $.09/KwHr equals = $.1971

Cost per day, week, month, year, etc then depends on how many hours the motor is operated in that timeframe.

Example:  The above motor is operated 18 hours per day.  So,

  • Cost per Day =  18 hr  x  $.1971/KwHr =  $3.5478 or $3.55
  • Cost per Week =  18 hr  x  7 days  x  $.1971/KwHr =  $24.8346 or $24.83

Let’s say the motor plate does not list the Kilowatt Rating nor is lit listed in literature or a web site and a representative is not available to help.  You can still come close, but you will have to calculate the Kilowatt Rating using the following formula;

The formula varies depending if the motor is 1-Phase or 3-Phase.  How do you know?  The motor plate should tell you that or your electrician can tell you.

1-Phase:      Kw =  I  x  E  x  Pf  /  1000

3-Phase:      Kw =  I  x  E  x  1.73  x  Pf  /  1000

Where;

  • Kw      Kilowatt Rating
  • I           Motor Amperage.  Find on motor label plate or measure with an Amp meter.
  • E          Motor Voltage.  Find on the motor label plate or measure with a Volt meter.
  • Pf         Power Factor.  Find on motor label plate or estimate with following table.

Power Factors:

  • 1/6 Hp                         .97
  • 1/3 Hp                         .91
  • 1 Hp                            .82
  • 2 Hp                            .78
  • 3 Hp (1-phase)             .99
  • 3 Hp (3-phase)             .70
  • 5 Hp                            .79
  • 10 Hp                          .91

Example:  A 2 Hp 1-Phase motor is operating at 230 Volts and has an Amperage draw of 11 Amps.  So,

Kw =  11  x  230  x  .78  /  1000  =  1.97 Kw

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